Question

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Answer 1

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The de- Broglie wavelength of electron is inversely proportional to its  velocity. So, when two electrons have the same velocity, they will have the same de- Broglie wavelength

We know that:                             V α  $\frac{Z}{n}$

where Z is the atomic number, and n is the orbit in which the electron is present

For Li²⁺ ion, n = 2 (given in the question)

so, $\frac{Z}{n}$ = 3/2

$\frac{Z}{n}$ for H = 1/3

$\frac{Z}{n}$ for C⁵⁺ = 6/4 = 3/2

$\frac{Z}{n}$ for Be³⁺ = 4/6 = 2/3

$\frac{Z}{n}$ for He⁺ = 2/3

So, de- Broglie wavelength will be same for both Li²⁺ and C⁵⁺ (since $\frac{Z}{n}$ are the same)

Answer 2

Answer:

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