Question

Help me get rid of this ques​

Answer 1

Answer:

c)1

Step-by-step explanation:

cos2x + 2sin²x

=cos(x+x) + 2sin²x

=cos²x- sin²x + 2sin²x {(cos(a+b)=cosa×cosb-sina×sinb)}

=cos²x + sin²x

=1

Answer 2

Answer:

ans:- 1

Step-by-step explanation:

$\cos(2x) = 1 - 2 \sin {}^{2} ( {x} )$

$1 - 2 { \sin {}^{2} (x) } + 2sin {}^{2} (x) = 1$