Question

help me give me a full answer this question please request ​

Answer 1

Answer:

1/2

Step-by-step explanation:

tanθ=1

θ=45

$\frac{(sin\theta+cos\theta)}{(sec\theta+cosec\theta)}\\\\=\frac{(sin45+cos45)}{(sec45+cosec45)}\\\\=\frac{\frac{1}{\sqrt{2} } +\frac{1}{\sqrt{2} } }{\sqrt{2}+\sqrt{2} } \\\\=\frac{\frac{2}{\sqrt{2}} }{2\sqrt{2}}\\\\=\frac{1}{2}$

Answer 2

Answer:

The value of :

sin theta + cos theta 1

sin theta + cos theta 2