Question

help me guys fastttt​

Answer 1

${4x}^{2} + 4x + 1 \\ {4x}^{2} + 2x + 2x + 1 \\ 2x(2x + 1) \: \: \: 1(2x + 1) \\ (2x + 1)(2x + 1) \\ 2x + 1 = 0$

$2x = - 1 \\ x = \frac{ - 1}{2} \\ \alpha = \frac{ - 1}{2} \: \: \: \: \: \: \beta = \frac{ - 1}{2}$

$2 \alpha = 2 \times \frac{ - 1}{2} = - 1 \\ 2 \beta = 2 \times \frac{ - 1}{2} = - 1$

${x}^{2} - (sum \: of \: zeroes)x + product \: of \: zeroes$

${x}^{2} - ( - 1 + - 1)x + ( - 1 \times - 1) \\ = {x}^{2} + 2x + 1$

Answer 2

HI Armyyy!!

Nice to meet you again :)

Well if you want you can answer my previous questions! Spam if you want or you can answer Irrevalently bcoz I already got the Answers I wanted

And once again Really really SORRYYYYY for being rude.

Take Care!!!

Also YOU can report this answer!