Question

HELP ME GUYS PLEASE​

Answer 1

Step-by-step explanation:

${x}^{3} - 4 {x}^{2} - 3x + 5 \\ \\ when = > \\ x - 3 = 0 \\ x = 3 \\ \\ {3}^{3} - 4 ({3}^{2}) - 3(3) + 5 \\ 27 - 36 - 9 + 5 \\ 23 - 36 \\ - 13$

Answer 2

Answer:

${x}^{3} - 4 {x}^{2} - 3x + 5$

$x - 3 = 0$

$x = 3$

$put \: x = 3 in \: given \: question$

${3}^{3} - 4 {3}^{2} - 3 \times 3 + 5$

$27 - 36 - 9 + 5$

$32 - 45= - 13$