Question

HELP ME GUYS
THIS IS PHYSICS QUESTION
CHAPTER IS CURRENT ELECTRICITY​

Answer 1

GIVEN:

I = 5A

n =5×10^26

e=1.6×10^-19 C

A =4×10^-6 m²

TO FIND:

V d (drift speed)=?

FORMULA

$i \: = n \: e \: a \: v$

• I = current
• n= electron density
• a = area of cross section
• v = drift speed

SOLUTION:

$v \: = \frac{i}{n \: e \: a} \\ v = \frac{5}{5 \times {10}^{26} \times 4 \times {10}^{ - 6} \times 1.6 \times {10}^{ - 19} } \\ v \: = 0.156 \times {10}^{ - 1} \\ v = 1.56 \times {10}^{ - 2}$