Question

help me guys urgent....​

Answer 1

Step-by-step explanation:

Let the interest rate be x%p.a. Principal amount is 4000 ruppees. It amounts to 4630.50 ruppees in 3 years at x%p.a. compounded yearly.

$4630.5 = 4000 {(1 + \frac{x}{100})}^{3} = > \frac{4630.5}{4000} =$

${(1 + \frac{x}{100}) }^{3} = \frac{9261}{8000} = > (1 + \frac{x}{100}) =$

$\sqrt[3]{ \frac{9261}{8000} } = \sqrt[3]{ \frac{ {21}^{3} }{ {20}^{3}}} = \frac{21}{20} = > \frac{21}{20} - 1 =$

$\frac{x}{100} = > \frac{1}{20} = \frac{x}{100} = > x = \frac{100}{20} = 5$

So the interest rate is 5%p.a. Compound interest for 4th year =>4630.5×5×1/100 =>231.53 ruppees. Hope it helps you.