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Write 15 chemical reaction and balance them and find the oxidized and reduced element and also oxidizing and reducing agents.
*First and the best answer will be Brainiest*
harsimransandhu3:
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1. CuO + H2 ---->. Cu + H2O
here copper oxide is being reduced to copper so, copper oxide is oxidising agent and hydrogen is reducing agent
2. H2S + Cl2 -------> S + 2HCl
here, chlorine is the oxidising agent and hydrogen sulphide is the reducing agent
3. ZnO + C ------> Zn + CO
here, zinc oxide is oxidising agent and carbon is reducing agent
4. MnO2 + 4HCl ------> MnCl2 + Cl2 + 2H2O
Here , manganese dioxide is the oxidising agent and hydrochloric acid is the reducing agent
5. 2Cu + O2 -----> 2CuO
oxygen is oxidising agent and copper is reducing agent
6. SO2 + 2H2S -----> 2H2O + 3S
here , SO2 is being reduced to S and H2S is being oxidised to S
7. H2S + I2 ------> 2HI + S
here iodine is oxidising agent and hydrogen sulphide is the reducing agent 8. 4Na + O2 --------> 2Na2O
here, the sustance oxidised is sodium and the substance reduced is Oxygen
here copper oxide is being reduced to copper so, copper oxide is oxidising agent and hydrogen is reducing agent
2. H2S + Cl2 -------> S + 2HCl
here, chlorine is the oxidising agent and hydrogen sulphide is the reducing agent
3. ZnO + C ------> Zn + CO
here, zinc oxide is oxidising agent and carbon is reducing agent
4. MnO2 + 4HCl ------> MnCl2 + Cl2 + 2H2O
Here , manganese dioxide is the oxidising agent and hydrochloric acid is the reducing agent
5. 2Cu + O2 -----> 2CuO
oxygen is oxidising agent and copper is reducing agent
6. SO2 + 2H2S -----> 2H2O + 3S
here , SO2 is being reduced to S and H2S is being oxidised to S
7. H2S + I2 ------> 2HI + S
here iodine is oxidising agent and hydrogen sulphide is the reducing agent 8. 4Na + O2 --------> 2Na2O
here, the sustance oxidised is sodium and the substance reduced is Oxygen
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