Question

Help me guyss.....

Find the value of K for which the point are collinear
(7,-2),(5,1),(3,k)

Answer 1

Answer:

area of triangle=0,because of given reason.

Step-by-step explanation:

1/2(7(1-k)+5(k+2)+3(-2-1))=0

7-7k+5k+10-9=0     (1/2 become 0 when it is go to the opposite side)

-2k+8=0

-2k=-8

k=-8/-2=4

k=4.