Question

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How is potential drop related to resistance when resistor are connected in series?

Answer 1

According to Ohm's law, the voltage drop, V, across a resistor when a current flows through it is calculated by using the equation V=IR, where I is current in amps (A) and R is the resistance in ohms (Ω). This implies that the total resistance in a series is equal to the sum of the individual resistances.

Answer 2

Answer:

Consider two resistances R1 and R2 connected in series with a battery having potential difference .Since in series combination current remains same.Let be the current in the circuit.

The equivalent resistance of the circuit,Rs = R1 + R2

V = IRs = I(R1 + R2)

= IR1 + IR2

V = V1 + V2

It means potential of battery is divided between the resistances in series in the circuit.