Question

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ALL THREE ANSWERS PLEASE

Answer 1

Step-by-step explanation:

(1) \frac{sin©}{1-cos©} + \frac{tan©}{1+cos©} \\ =\frac{sin©(1+cos©)+tan©(1-cos©)}{(1-cos©)(1+cos©)

\frac{sin©}{1-cos©} + \frac{tan©}{1+cos©} \\ =\frac{sin©(1+cos©)+tan©(1-cos©)}{(1-cos©)(1+cos©)[tex] \frac{sin©}{1-cos©} + \frac{tan©}{1+cos©} \\ =\frac{sin©(1+cos©)+tan©(1-cos©)}{(1-cos©)(1+cos©)} \\ = \frac{sin©+sin©cos©+tan©-tan©cos©}{1-cos²©} \\ = \frac{sin©+sin©cos©+tan©-sin© }{sin²©} \\ = cot©+cosec©Sec© \\ (2) \\ sec⁴© - sec²© \\ =sec²©(sec²©-1) \\ =sec²©(tan²©) \\ =(1+tan²©)(tan²©) \\ = tan²©+tan⁴©

here © =(θ)

(2)

Answer 2

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