Question

help me I need the ans​

Answer 1

Step-by-step explanation:

in ∆ABC &∆ADE

AD=AB (GIVEN)

AC=AE (GIVEN)

SINCE ANGLE (BAC)=ANGLE BAD +ANGLE DAC

AND. ANGLE DAE=DAC+CAE

THEREFORE

ANGLE BAC =ANGLE EAD

THEN ∆ABC CONGRUENCE ∆ADE

THEREFORE

BC=DE (CPCT)

PROVED

Answer 2

Step by step explanation:

Given:

AC = AE, AB = AD and ∠BAD = ∠EAC

To prove: BC = DE

Solution:

Given that: ∠BAD = ∠EAC

Add ∠DAC on both sides

⇒ ∠BAD + ∠DAC = ∠EAC + ∠DAC

⇒ ∠BAC = ∠EAD

Now,

In ΔABC and ΔADE,

⇒ AC = AE ___ (Given)

⇒ ∠BAC = ∠EAD ___ (Already proven)

⇒ AB = AD ___ (Given)

Hence, ΔABC ≅ ΔADE ___ By SAS congruency rule

Therefore,

By c.p.c.t, BC = DE

Hence, Proved.