Question

help me if anyone there...​

Answer 1

Answer:

Correct answer: (c)  

Solution:             Eq of Al= eq of H2                     4.5273=eq of H2;  4.59=eq of H2                     2H++2e−→H2                    eq. of H2 = Number of moles × n factor 0.5=nH2×2                                 VH2=0.52×22.4; VH2=5.6 L

Explanation:

Answer 2

Answer:

I asked for a good friend

Explanation:

not for bad purp0se