Question

help me if possible integrate this
∫ (x2/(x-3)dx

Answer 1

Answer:

2(x-3) + 6log|x-3|+C

Step-by-step explanation:

∫ (x2/(x-3))dx

let (x-3)=t

so, dx=dt

there for ∫ (2(t+3)/t)dt

= ∫ (2t/t)dt +∫ (6/t)dt = ∫ (2)dt +6∫(1/t)dt

=2t + 6log|t| + C

=2(x-3) +6log|x-3| + C