Question

Help me in Q6 please its to urgent tommorow is my exam please please explain me properly

Answer 1

P(height from ground) = 8m
B (distance from wall )= 6m
H (Length of ladder)= ?

Apply Pythagoras theorem to find hypotenuse which is ladder height.

$h {}^{2} = p {}^{2} + b {}^{2}$

$h {}^{2} = 8 {}^{2} + 6 {}^{2}$

$h {}^{2} = 64 + 36 = 100$


$h = \sqrt{100} = 10m$

Ladder height is 10m.

Now we have to find height from the ground when it is shifted 8m away from the wall.

So.

h = 10
b = 8
p = ?

$p {}^{2} = h {}^{2} - b {}^{2}$

$p {}^{2} = 10 {}^{2} - 8 {}^{2}$

$p {}^{2} = 100 - 64 = 36$


$p = \sqrt{36} = 6m$


So top reaches to the 6m.


Thanks