Math, asked by Irony14, 1 year ago

help me in question of maths....Q no.8,9,10,11,12...

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Answers

Answered by suprita12
1
8 no. done
9. no. done
10.no.done
11.no. done
12.no.done I.e
rationalize the no.s
 (\sqrt{32} +  \sqrt{48} ) \div  (\sqrt{8}  +  \sqrt{12})   \times  (\sqrt{8 }  -  \sqrt{12}  )\div  (\sqrt{8}  -  \sqrt{12})  \\  =  ((\sqrt{32}  +  \sqrt{48} ) \times ( \sqrt{8 } -  \sqrt{12} ) )\div  - 4 \\  = ( \sqrt{32} \times  \sqrt{8}  -  \sqrt{32}    \times  \sqrt{12}  +  \sqrt{48}  \times  \sqrt{8}  -  \sqrt{48}  \times  \sqrt{12}  )\div  - 4 \\  =  (\sqrt{256}  -  \sqrt{384} +  \sqrt{384}  -  \sqrt{576} ) \div  - 4 \\  = (16 - 24) \div  - 4 \\  =  - 8 \div  - 4 \\  =  2
the √256 =16 and √576=24
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Irony14: suprita thankyou very much
Irony14: it is my holiday home work
Irony14: and no body is helping me
suprita12: wc bt aage se tum khud karne ki koshish karna.... try to do yourself..
Irony14: okkkkkkkk
Irony14: do you know how to delete wrong answer in brainly
suprita12: edit option is there
suprita12: no. 10 answer is 14 .. actually i am forget to squaring of 4
suprita12: 4^2-2= 16-2=14 ohk baki sab thik hai
Irony14: okkk
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