Question

help me in solving this equation ​

Answer 1

Answer:

x = 0, y = -3 and p = 2

Step-by-step explanation:

$3x-2y=6     ....(i)\\(x/3)-(y/6)=1/2\\6x-3y/18 =1/2\\2x-y=3\\x=3+y/2      ....(ii)\\substituting\\the\\value of x \\in (i)\\we get \\2(3+y/2)-2y=6\\9+3y-4y=12\\y=-3\\now for p \\x-py=6 keeping all the values we get \\p=2$