Question

help me in the first sum....no spam...use the given formula
$amount = p \times 1 + r \div100 whole \: power \: n$

Answer 1

$<b><u><i>Heya mate!!! Here's your solution</i></u>$
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$\huge{To\: Find}$

The amount and the compound interest on 12000 Rs. in 3 years at 5%, interest being compounded annually.

$\huge{Solution}$

Principal amount (P) = 12000 Rs.

Time (n) = 3 years

Rate of interest (R) = 5% p.a.
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Now, we know that,

Amount (A) = P (1+R/100)^n

$= > A = 12000 \times (1 + \frac{5}{100} ) ^{3}$

$= > A = 12000 \times ( \frac{100 + 5}{100} ) ^{3}$

$= > A = 12000 \times ( \frac{105}{100} ) ^{3}$

$= > A = 12000 \times ( \frac{21}{20} ) ^{3}$

$= > A = 12000 \times \frac{21}{20} \times \frac{21}{20} \times \frac{21}{20}$

$= > A = \frac{11113200}{8000}$

$= > A = 13891.5$

Hence, A = 13891.5 Rs.

Now, we know that,

Compound interest (C.I)

= A - P

= 13891.5 - 12000

= 1891.5

Hence, C.I = 1891.5

$\mathcal{Finally,}$

Your answers are -

$\boxed{\bold{\blue{\mathcal{Amount \: = \: 13891.5 \: Rs}}}}$
$\boxed{\bold{\blue{\mathcal{Compound\: interest\: = \: 1891.5}}}}$
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$\huge{\bold{\red{\mathfrak{Thank\: you}}}}$