help me in this indices prb
Attachments:
Answers
Answered by
1
1/1+loga(bc)
=1/loga(a)+loga(bc)
=1/loga(abc)
=logabc(a)
Similarly doing this for other ones it will come that,
logabc(a)+logabc(b)+logabc(c)
=logabc(abc)
=1(ans.)
=1/loga(a)+loga(bc)
=1/loga(abc)
=logabc(a)
Similarly doing this for other ones it will come that,
logabc(a)+logabc(b)+logabc(c)
=logabc(abc)
=1(ans.)
parilharsha0482:
thank you sir
Similar questions