Question

Help me in this ques... correct ans will be mark as brainliest​

Answer 1

here is your answer

Step-by-step explanation:

when both roots will be squred then only no.will left

Answer 2

Answer:

x = 6

Step-by-step explanation:

$\sqrt{x+3}+\sqrt{x-2} = 5\\\\ Squaring*on *both* sides, we*get\\\\=>(\sqrt{x+3}+\sqrt{x-2})^{2} = 5^{2}\\\\=>2x+1+2\sqrt{x^{2}+x-6}=25\\\\ => 2x+2\sqrt{x^{2}+x-6}=24\\\\=>2\sqrt{x^{2}+x-6}=24-2x\\\\Now*once*again*squaring*on*both*sides,we*get\\\\4(x^{2}+x-6)=(4x^{2} -96x+576)\\\\=>4(x^{2} +x-6)=4x^{2} -96x+576\\\\=>4x^{2} +4x-24=4x^{2} -96x+576\\\\=>100x=600\\\\=>x=6$

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