Question

help me in this question​

Answer 1

Given:-

$k = 2.54 \times {10}^{ - 3} {s }^{ - 1}$

FIND:-

${ \frac{3}{4} }^{th} life$

SOLUTION:-

$amount \: of \: reactant \: left = \frac{[R]_0}{4}, where \: [R]_0 \: is \: the \: initial$

$concentration \: of \: the \: reactant.$

$for \: a \: first \: order \: reaction,$

$t = \frac{2.303}{k} log \frac{[R]_0}{ \frac{[R]_0}{4} }$

$t = \frac{2.303}{2.54 \times {10}^{ - 3} } log4 = 906.69 \times 0.6021$

$t = 545.918 = 5.46 \times {10}^{2} s$