Question

help me in this question​

Answer 1

${( \frac{4}{7} )}^{3} = {( \frac{4}{7} )}^{2} \times { {( \frac{4}{7} }^{3} )}^{2x - 1}$

As, these are all now like terms, we can equate the powers :-

3 = 2(3(2x-1))

3 = 12x - 6

12x = 9

X = 3/4

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