Question

help me in this question
by describing it

Answer 1

$x = 30 \: by \: corressponding \: angle 40 + 30 + y = 180 \: sum \: of \: all \: angles \: of \: triangle \\ y = 180 - 70 = 110 \\ now \\ 40 + x +z = 180 \: {sum \: of \: all \: angles \: of \: triangle} \\ z = 180 - 70 = 110$

Answer 2

DC ll BC
$x \: = 30 \: ( \: corressponding \: angle \: ) \\ < dae + x + y = 180 \: (sum \: of \: all \: angle) \\ y + 30 + 40 = 180 \\ y + 70 = 180 \\ y = 180 -70 = 110 \\ now \\ < a + x + z = 180 \:( sum \: of \: all \:angle) \\ 40 + 30 + z = 180 \\ 70 + z = 180 \\ z = 180 - 70 = 110$