Question

help me in this question I'll mark you as a brainliest

Answer 1

Hello mate,

we know
cos (90-x) = sinx
sec (90-x) = 1/cos (90-x ) = 1/sinx
tanx = sinx/cosx
cosec (90-x) = 1/sin (90-x) = 1/cosx
sin (90-x) = cosx
cot (90-x) = cos (90-x)/sin (90-x) = sinx/cosx

so just plug in the values in the equation,

[sinx × 1/sinx × sinx/cosx/(1/cosx × cosx × sinx/cosx) ] + cosx/sinx/cosx/sinx

now cancel like terms and multiply like terms if any,

1 + 1 = 2

hope this helps you out!

Answer 2

Answer:

Step-by-step explanation: