Question

help me in this question ❓ please​

Answer 1

Answer:

1.  191250 $cm^{3}$

2. 42750 $cm^{3}$

3. 3420 g

Step-by-step explanation:

Outer dimensions of the box (l×w×h) = 80 cm × 65 cm× 45 cm

Thickness of wood = 2.5 cm

So, the internal dimensions of the box = (80−2.5×2) × (65−2.5×2) × (45−2.5) = 75 cm× 60 cm× 42.5 cm

Therefore, capacity of the box = 75 cm × 60 cm × 42.5 cm= 191250 $cm^{3}$

Volume of wood used = Outer volume of box - inner volume of box

Outer volume of box = 80c m× 65 cm× 45 cm= 234000 $cm^{3}$

Volume of wood used = 234000 $cm^{3}$ − 191250 $cm^{3}$ = 42750 $cm^{3}$

It is also given that 100$cm^{3}$ of wood weighs = 8g

So, weight of box = 8/100  × 42750 = 3420 g

Answer 2

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