Question

help me in this questions​

Answer 1

Answer:

${\frac{{x}^{2}-4}{x+2} }÷{ \frac{{x}^{3}-8}{{x}^{2}+2x+4}}$

${\frac{{x}^{2}-4}{x+2}} × {\frac{{x}^{2}+2x+4}{{x}^{3}-8}}$

By id a³-b³ = (a-b)(a²+2ab+b³)

$\frac{{x}^{2}-4}{x+2} × \frac{{x}^{2}+2x+4}{(x-2)({x}^{2}+2x+4)}$

$\frac{{x}^{2}-4}{x+2} × \frac{1}{x-2}$

By id (a²-b²)=(a+b)(a-b)

$\frac{(x-2)(x+2)}{x+2} × \frac{1}{x-2}$

All are cancelled

Answer = 1

HOPE IT HELPS...