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Answer:∠BOC=130°
Step-by-step explanation:
In ΔABC,
A+B+C=180°(Angle sum property of aΔ)
80°+40°+c=180°
120°+C=180°
C=60°
Then,
since OB and OC are bisectors of ∠B and ∠C.
∴∠OBC= 40°/2=20° and ∠OCB= 60°/2=30°
Now,
∴∠OBC+∠OCB+∠BOC=180°(Angle sum property of aΔ)
20°+30°+∠BOC=180°
50°+∠BOC=180°
∠BOC=130°
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Answer:
please mark as brilliant C=60⁰
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