Question

Help me in this trigonometry solution
Cot^2theta(sec theta -1)/(1+sin theta)=sec^2theta*(1-sin theta/1+sec theta)

Answer 1

Step-by-step explanation:

{cot sq. theta(sec theta -1)}/(1+sin theta)

(cos sq. theta/sin sq. theta){(sec theta-1)/(1+sin theta)}

$. (cos sq. theta/sin sq. theta){(tan sq. theta/sec theta -1)(1/1+sin theta)

₹. (cos sq. theta/sin sq. theta){(tan sq. theta)/(sec theta+1)×(1-sin theta)/cos sq. theta

@( 1/sin sq. theta)×(sin sq.theta)/ ( cos sq. theta×(sec theta +1)) ×1- sin theta

{sec sq.theta(1-sin theta)}/1+sectheta

Modification of identities (cos sq theta +sin sq theta=1)and (sec sq. theta - tan sq theta =1) are used in $ and ₹.

hence Proved

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