Help me it is urgent
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Answer:
sum of the interior angles of a Quadrilateral=360°
1. ∠BAD+71.4°+59.1°+96.2°=360°
∠BAD=133.3°
Step-by-step explanation:
Sum of the interior angles of a polygon =(n-2)*180
where, n is the number of sides of the polygon.
I'm sure you got an idea to solve the remaining ones
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