Help me it is urgent
Attachments:

Answers
Answered by
1
Answer:
sum of the interior angles of a Quadrilateral=360°
1. ∠BAD+71.4°+59.1°+96.2°=360°
∠BAD=133.3°
Step-by-step explanation:
Sum of the interior angles of a polygon =(n-2)*180
where, n is the number of sides of the polygon.
I'm sure you got an idea to solve the remaining ones
Similar questions