Math, asked by dreamboi07, 9 months ago

Help me

It's urgent yr.......xD​

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Answers

Answered by Anonymous
8

Ye le vhai chap daala maine....

3+√7 / 3-√7

multiply 3+√7 on both numerator and denomerator

(3+√7)² / (3-√7)(3+√7) = a+b√7

⇒9 + 7 + 6√7 / 3² -√7² = a+b√7

⇒16+ 6√7 / 9-7 =a+b√7

⇒16+ 6√7 / 2 =a+b√7

⇒2(8+3√7)/2 =a+b√7

⇒8 +3√7 =a+b√7

on compairing both sides

a=8

b=3

Answered by ғɪɴɴвαłσℜ
4

Aɴꜱᴡᴇʀ

 \huge \tt \blue{a = 8} \\  \\ \huge \tt \blue{b = 3}

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Gɪᴠᴇɴ

 \large \tt  \frac{3 +  \sqrt{7} }{3 -  \sqrt{7} }  = a + b \sqrt{7}

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ᴛᴏ ꜰɪɴᴅ

The valur of "a" and "b"

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Sᴛᴇᴘꜱ

Let's rationalise the denominator to find our answer

Note:-

  • Multiply the number with its opposite sign

So ,

 \large \tt  \frac{3 +  \sqrt{7} }{3 -  \sqrt{7} }   \times  \frac{3 +  \sqrt{7} }{3 +  \sqrt{7} }  \\  \\  \large \tt{} \frac{9 + 3 \sqrt{7 } + 3 \sqrt{7}  + 7 }{9 - 7}  \\  \\  \large \tt{} \frac{16 + 6 \sqrt{7} }{2}   \\  \\  \large \tt here \: 2 \: is \: common \: for \: both \: so  \\  \\  \large \tt{} \frac{ \cancel{16}}{ \cancel2}  +  \frac{ \cancel6 \sqrt{7} }{ \cancel2}  \\  \\  \large \tt{}  \pink{\dashrightarrow{}8 +3 \sqrt{7}  } \\  \\  \large \tt{}thus \: the \: value \: of \:   \green{a = 8} \:  and \:  \orange{b = 3}

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\huge{\mathfrak{\purple{hope\; it \;helps}}}

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