Question

HELP me on this question and plzz find perimeter of rohmud​

Answer 1

kk this is my answer

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Answer 2

Answer:

A very important property of rhombus should be noted that diagonals of a rhombus bisect each other at 90°.

Step-by-step explanation:

Let ABCD be a rhombus (as shown in the image), whose diagonal AC is 16 cm and BD is 30 cm.

So,

Given:- AC = 16 cm

BD = 30 cm

since, diagonals bisect each other at 90° in rhombus,

thus, Angle AOB =90°

& AO =1/2 * AC = 1/2 * 16 = 8 cm

& BO =1/2 * BD = 1/2 * 30 = 15 cm

Since, Triangle AOB is a right angled triangle,

thus, by Pythagoras theorem,

(AO)² + (BO)² = (AB)²

=>8² + 15² = AB²

=>64 + 225 = AB²

=>289 = AB²

=> AB =

$\sqrt{289}$

=> AB = 17 cm = Side of the rhombus

Since, perimeter of rhombus = 4 * Side of rhombus

=> Perimeter = 4 *17=68 cm