Question

Help me only last question it is..

Answer 1

hey mate the answer is 12 cm2

Answer 2

By mid-point theorem in (PEQ)

F is the mid point of PE.

[Since R is mid point of QE (QR=RE) and SR||PQ (||gm PQRS).]

So

=>2RF=PQ.

PQ=SR (||gm)

=> 2RF=SR

Hence F is the midpoint of SR.

In (QSR) QF is the median. Hence SQF=QFR= 3cm square

In || PQRS, diagonal QS divides it into two equal triangles i.e. QPS=QSR

QSR= QSF+QFR

=> 3+3= 6 cm square.

2 ar(QSR) = ||gm PQRS (QPS=QSR)

=> PQRS= 12 cm square.

Hence the area of parallelogram PQRS is 12 cm square.

Hope this helped!