Question

help me out ☹️☹️..........​

Answer 1

To Find :-

• Value of x

Solution :-

We have,

• $\sf \dfrac{5}{4} (7x - 3) - \Bigg(4x - \dfrac{1 - x}{2} \Bigg) = x - \dfrac{3}{2 }$

Now,

$\sf : \implies \dfrac{5}{4} (7x - 3) - \Bigg(4x - \dfrac{1 - x}{2} \Bigg) = x - \dfrac{3}{2}$

$\sf : \implies \dfrac{5 \times 7x}{4} - \dfrac{5 \times 3}{4} - \Bigg(\dfrac{8x}{2} - \dfrac{1 - x}{2} \Bigg) = \dfrac{2x}{2} - \dfrac{3}{2}$

$\sf : \implies \dfrac{35x}{4} - \dfrac{15}{4} - \Bigg(\dfrac{8x - 1 + x}{2} \Bigg) = \dfrac{2x - 3}{2}$

$\sf : \implies \dfrac{35x}{4} - \dfrac{15}{4} - \Bigg(\dfrac{9x - 1}{2} \Bigg) = \dfrac{2x - 3}{2}$

$\sf : \implies \dfrac{35x}{4} - \dfrac{15}{4} - \dfrac{9x - 1}{2} = \dfrac{2x - 3}{2}$

$\sf : \implies \dfrac{35x}{4} - \dfrac{15}{4} - \dfrac{(9x - 1) \times 2}{2 \times 2} = \dfrac{2x - 3}{2}$

$\sf : \implies \dfrac{35x}{4} - \dfrac{15}{4} - \dfrac{18x - 2}{4} = \dfrac{2x - 3}{2}$

$\sf : \implies \dfrac{35x - 15 - (18x - 2)}{4} = \dfrac{2x - 3}{2}$

$\sf : \implies \dfrac{35x - 15 - 18x + 2}{4} = \dfrac{2x - 3}{2}$

$\sf : \implies \dfrac{17x - 13}{4} = \dfrac{2x - 3}{2}$

$\sf : \implies (17x - 13) \times 2 = (2x - 3) \times 4$

$\sf : \implies 34x - 26 = 8x - 12$

$\sf : \implies 34x - 26 - 8x + 12 = 0$

$\sf : \implies 26x = 14$

$\sf : \implies x = \cancel{\dfrac{14}{26}}$

$\sf : \implies x = \dfrac{7}{13}$

$\bf Hence, \: value \: of \: x \: is= \dfrac{7}{13}$

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Answer 2

$\large \red{\bf \: ⟼ Question :- } ✍$

$</p><p> \bf \dfrac{5}{4} (7x - 3) - \Bigg(4x - \dfrac{1 - x}{2} \Bigg) = x - \dfrac{3}{2 }</p><p>$

$\huge \orange{AηsωeR} ✍$

$\large \red{\bf \: ⟼ Given :- } ✍$

$</strong></p><p><strong>[tex] \bf \dfrac{5}{4} (7x - 3) - \Bigg(4x - \dfrac{1 - x}{2} \Bigg) = x - \dfrac{3}{2 }</strong></p><p><strong>[tex] \bf \dfrac{5}{4} (7x - 3) - \Bigg(4x - \dfrac{1 - x}{2} \Bigg) = x - \dfrac{3}{2 }$

$\large \red{\bf \: ⟼ To Find :- } ✍$

Value of x

$\large \red{\bf \: ⟼ Solution:- } ✍$

$</p><p> \bf \dfrac{5}{4} (7x - 3) - \Bigg(4x - \dfrac{1 - x}{2} \Bigg) = x - \dfrac{3}{2 }</p><p>$

$</p><p> \bf ⟼\dfrac{5}{4} (7x - 3) - \Bigg( \dfrac{8x - 1 + x}{2} \Bigg) = x - \dfrac{3}{2 }</p><p>$

$\bf \: ⟼ \dfrac{35x - 15}{4} - \dfrac{9x - 1}{2} = \dfrac{2x - 3}{2}$

$\bf \: ⟼ \dfrac{35x - 15 - 18x + 2}{4} = \dfrac{2x - 3}{2}$

$\bf \: ⟼ \dfrac{17x - 13}{4} = \dfrac{2x - 3}{2}$

$\bf \: ⟼ 17x - 13 = 4x - 6$

$\bf \: ⟼ 17x - 4x = 13 - 6$

$\bf \: ⟼ 13x = 7$

$\large \red{\bf \: ⟼ x = \dfrac{7}{13} }$

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