Question

Help me out guys.......

Answer 1

a = 0

b = - 6

Answer:

let ,$f(x) = {x}^{2} + (a + 1)x + b$

and, the zeroes of the polynomial f(x) be as

• $\alpha = 2$
• $\beta = - 3$

Now,

sum of zeroes,

$\longmapsto \alpha + \beta = - \frac{(a + 1)}{1}$

$\Rightarrow 2 + ( - 3) = - (a + 1)$

$\Rightarrow 2 - 3 = - a - 1$

$\Rightarrow - 1 = - a - 1$

$\Rightarrow a = 1 - 1$

$\Rightarrow a = 0$———————( 1 )

And,

product of zeroes,

$\longmapsto \alpha . \beta = \frac{b}{1}$

$\Rightarrow 2 \times ( - 3) = \frac{b}{1}$

$\Rightarrow - 6 = b$

$\Rightarrow b = - 6$

Step-by-step explanation:

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