Question

help me out guys
Open CHALLENGE
Show me what YA got

Answer 1

1/(1+logb(ac))+1/(1+logc(ab))+1/(1+loga(bc))
1/(logb(b)+logb(ac))+1/(logc(c)+logc(ab))+1/(loga(a)+loga(bc))

1/(logb(bac))+1/(logc(cab))+1/(loga(abc))

logbac(b)+logcab(c)+logabc(a)
logabc(a*b*c)=logabc(abc)=1 ansr
B option is ryt