Question

help me out guys pls​

Answer 1

Hope it helps...........

Answer 2

1) . Given

${x}^{2} + {y}^{2} = 14 \: and \: \\ xy = 5$

To find

$(x + y) {}^{2}$

${x}^{2} + {y}^{2} + 2xy \\ = > 14 + 2(5) \\ = > 14 + 10 \\ = > 24$

2). Given

$(x + y) {}^{2} = 361 \: and \: \\ xy = 120$

To find

${x}^{2} + {y}^{2}$

....

$(x + y) {}^{2} = 361 \\ = > {x}^{2} + {y}^{2} + 2xy = 361 \\ = > {x}^{2} + {y}^{2} + 2(120) = 361 \\ = > {x}^{2} + {y}^{2} = 361 - 240 \\ = > {x}^{2} + {y}^{2} = 121$