Physics, asked by Anonymous, 7 months ago

help me out guys ....pls...
itz too urgent...​

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Answers

Answered by ashik3050
1

Answer:

(1) 0.16Nm^-2 [It's the same for all cases]

(2) 14.28m^2

(3) 20Nm

(4) 16N

Explanation:

Answered by Anonymous
24

hlo sis ❣

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1. given

force = 40 N

area of first side = 25×10 = 250 cm^2 = 2.50 m^2

area of second side = 10×5 = 50 cm^2 = 0.50 m^2

area of third side = 5×25 = 125 cm^2 = 1.25 m^2

pressure = force × area

so ,

pressure exerted in first case = 40×2.50 = 100 N/m^2

pressure exerted in second case = 40×0.50 = 20 N/m^2

pressure exerted in third case = 40×1.25=50 N/m^2

________________________

2.force = 1500 N

pressure = 105 N/m^2

area = ?

area = pressure/force = 105/1500 = 0.07 m = 7cm

________________________

3.force = 20 N

distance = 1 m

moment of force = force × distance = 20 ×1 = 20 N/m

________________________

4.distance = 25 cm = 0.25 m

moment of force = 4 Nm

force = ??

force = moment of force/ distance = 4 / 0.25 = 16 N

_________________________

hope it helps

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