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Answers
Explanation:
Question

A person standing at the junction (crossing) of two straight paths represented by the equations 2x−3y+4 = 0 and 3x+4y−5= 0 wants to reach the path whose equation is 6x−7y+8= 0 in the least time. Find equation of the path that he should follow.
Medium
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Solution

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Given a person is standing at the junction of the below lines
2x−3y+4=0 ...(1)
3x+4y−5=0 ...(2)
Solving equation (1) and (2) ,we get
x=−171 and y=1722
So, the person is standing at point (−171,1722)
Given equation of path is
6x−7y+8=0 ...(3)
The person can reach this path in the least time if he walks along the perpendicular line to (3) from point (−171,1722)
Slope of the line (3)=76
∴ slope of the line perpendicular to line (3)=−761=−67
The equation of the line passing through (−171,1722) and having a slope of −
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Answer:
Explanation:
Question

A person standing at the junction (crossing) of two straight paths represented by the equations 2x−3y+4 = 0 and 3x+4y−5= 0 wants to reach the path whose equation is 6x−7y+8= 0 in the least time. Find equation of the path that he should follow.
Medium
Open in App
Solution

Verified by Toppr
Given a person is standing at the junction of the below lines
2x−3y+4=0 ...(1)
3x+4y−5=0 ...(2)
Solving equation (1) and (2) ,we get
x=−171 and y=1722
So, the person is standing at point (−171,1722)
Given equation of path is
6x−7y+8=0 ...(3)
The person can reach this path in the least time if he walks along the perpendicular line to (3) from point (−171,1722)
Slope of the line (3)=76
∴ slope of the line perpendicular to line (3)=−761=−67
The equation of the line passing through (−171,1722) and having a slope of −
Explanation:
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