Question

help me out if u can​

Answer 1

Step-by-step explanation:

given

40 ,42,45,x -1 ,x +2,51,54,62

meadian = 49

so aa we can see number of observation= n = 8 even

so

$meadian = \frac{ \frac{n}{2}th \: obeservation \: + ( \frac{n}{2} + 1)th \: observation}{2}$

put n =8 n median = 49 we get

$49 = \frac{ \frac{8}{2} th + \frac{8}{2} + 1th} {2}$

$49 = 4th \: + 5th \div 2$

$49 \times 2 = x - 1 + x + 2$

$98 = 2x + 1$

$98 - 1 = 2x$

$97 = 2x$

$\frac{97}{2}$

$x = 48.5$

no put value we get

x -1 = 48.5 -1 =47.5

x +2 = 48.5+2=50.2

for mean

as we know formula

$mean = \frac{sum \: of \: observation}{tota \: numberof \: observation}$

$mean \: = \frac{40 + 42 + 45 + 47.5 + 50.5 + 51 + 54 + 62}{8}$

mean =

$\frac{392}{8}$

mean =49