help me out ......
please
Attachments:
Answers
Answered by
2
Given 3 log x + 1/2 log y = 2
We know that a lob b = log b^a.
log x^3 + log y^1/2 = 2
log(x^3 * y^1/2) = 2
x^3 * y^1/2 = 10^2
y^1/2 = 100/x^3
y = (100/x^3)^2
y = 10000/x^6.
We know that a/b^n = ab^-n
y = 10000 x^-6.
Hope this helps!
We know that a lob b = log b^a.
log x^3 + log y^1/2 = 2
log(x^3 * y^1/2) = 2
x^3 * y^1/2 = 10^2
y^1/2 = 100/x^3
y = (100/x^3)^2
y = 10000/x^6.
We know that a/b^n = ab^-n
y = 10000 x^-6.
Hope this helps!
VishnuRaj1:
perfect answer thank you soooooo much
Thanks Vishnu
i have another doubt
What's that?
i have askd plzz just see
What is ur doubt ?
another sum
Ohkk..I thought your doubt is regarding this problem.
Similar questions