Physics, asked by PremanandGupta, 1 year ago

Help me out please...........

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Answered by vijaya2002
0

h=150m (x=distance b/w top &the position at which 2 bodies

s=ut=1/2at^2 meet)

x=gt^2/2...............(1)

150-x=30t-gt^2/2

150-gt^2/2=30t-gt^2/2

150=30t

t=150/30

t=50sec

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