help me out please.can you?
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PQ=PS=5cm
PR is perpendicular side QS
apply pythagoras in triangle PRQ
PR=4CM
PERIMETER of triangle PQR= QR+PR+PQ
=3+4+5
=12cm
PR is perpendicular side QS
apply pythagoras in triangle PRQ
PR=4CM
PERIMETER of triangle PQR= QR+PR+PQ
=3+4+5
=12cm
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Answered by
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Answer:
PQ=PS=5cm
PR is perpendicular side QS
apply pythagoras in triangle PRQ
PR=4CM
PERIMETER of triangle PQR= QR+PR+PQ
=3+4+5
=12cm
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