Question

help me out please I really need help
urgent....​

Answer 1

Step-by-step explanation:

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See The Attachment My Friend....

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Answer 2

Answer:

(i)1683

(ii) 7500

Step - by - Step explanation:

(i) 108,117,126.... 198 and so on

So a=108

l=198

n= ?

nth term= a + (n-1)d

198= 108+(n-1)9

198= 108+9n-9

198-99= 9n

99/9= n

n= 11

Now, sum of n terms

Sum of first 11 terms= 11/2(108+198)

=11/2(306)

=11×153

=1683

(ii) all odd integers between 100 and 200 are 101,103,105........199

here,

a=101

d=2

tn=199

to find Sn

tn=a+(n-1)d

199=101+(n-1)2

199-101=(n-1)2

98=2n-2

98+2=2n

100=2n

n=50

Sn=n/2(a+tn)

Sn=50/2(101+199)

Sn=25(300)

Sn=7500

Hence, the sum of all odd integers between 100 and 200 is 7500

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