help me out please the 1st sum
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i hope this will usful to u
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1.(i) angle ADE = angle B (given)
and ,angle A = angle A (common)
so ,by AA criteria - ∆ABC–∆ADE
(ii).if ∆ABC –∆ ADE
then ,AB/AD = BC/DE= AC/AE
AE+EB/AD= BC/DE
5.7/3.8=4.2/DE
4.2×3.8/5.7= DE
so,DE= 2.8
and ,angle A = angle A (common)
so ,by AA criteria - ∆ABC–∆ADE
(ii).if ∆ABC –∆ ADE
then ,AB/AD = BC/DE= AC/AE
AE+EB/AD= BC/DE
5.7/3.8=4.2/DE
4.2×3.8/5.7= DE
so,DE= 2.8
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