Question

help me out plzzz.....no.24

Answer 1

All capacitors are in parellel

So,
Equivalent capacitance = 1 μF + 2 μF + 3 μF = 6 μF

Energy stored = 0.5CV²
= 0.5 × 6 μF × (10 V)²
= 300 μJ

Answer 2

Hey !

In the given figure all the capacitors are parallel,

Equivalent capacitance (E.C) = 1μF + 2μF + 3μF

= 6 μF

So,

Therefore energy stored is 0.5 CV²

=> 0.5 × 6 μF × ( 10 V )²

=> 300 μJ (FINAL ANSWER)