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AnjaliRoy00:
7/5 × u/g is your answer
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Answer: 21/25×h
Explanation:
Time taken by ball to reach maximum height = time taken by ball to hit ground.
The velocity at the maximum height = 0
hence, H=1/2gt^2
where g is the acceleration due to gravity, t is the time taken by ball to cover a distance H
At time 7t/5, the ball would be in downward motion. we need to find the distance covered in 7t/5-t =2t/5 because time t is taken in the upward flight.
After 2t/5 time from the maximum height, distance covered,
s=1/2×g(2t/5)^2=2/25gt^2=4/25×h
Hence, the height of the ball from the ground,
H-4/25×H=21/25×H
Hope it helps you
Explanation:
Time taken by ball to reach maximum height = time taken by ball to hit ground.
The velocity at the maximum height = 0
hence, H=1/2gt^2
where g is the acceleration due to gravity, t is the time taken by ball to cover a distance H
At time 7t/5, the ball would be in downward motion. we need to find the distance covered in 7t/5-t =2t/5 because time t is taken in the upward flight.
After 2t/5 time from the maximum height, distance covered,
s=1/2×g(2t/5)^2=2/25gt^2=4/25×h
Hence, the height of the ball from the ground,
H-4/25×H=21/25×H
Hope it helps you
mark it as brainliest
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Hope this will help u... :-)
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handwriting was to good
Hahaha.. Thanx.
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