Math, asked by bishtdiya16, 9 months ago

Help me out with the 2nd one plzzz

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Answers

Answered by sandy1816
2

Step-by-step explanation

2.LHS

sinA/cotA+cosecA

=sinA/(cosA/sinA)+(1/sinA)

=sinA/(cosA+1/sinA)

=sin²A/1+cosA

=1-cos²A/1+cosA

=1-cosA

RHS

2 + sinA/cotA-cosecA

=2 + sinA/(cosA/sinA)-(1/sinA)

=2 + sinA/(cosA-1)/sinA

=2+ sin²A/cosA-1

=2- sin²A/1-cosA

=2- (1-cos²A)/1-cosA

=2-(1+cosA)

=2-1-cosA

=1-cosA

LHS=RHS

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