Question

help me out with this​

Answer 1

Answer:

So sorry

BUT I DON'T KNOW

Answer 2

Answer:

1/2

Step-by-step explanation:

tan theta = 1/$\sqrt{3}$

theta = 30

cosec theta =cosec 30 = 2

sec theta = sec 30 = 2/$\sqrt{3}$

To find: $\frac{cosec^2 theta - sec^2 theta}{cosec^2 theta + sec^2 theta}$

         = $\frac{2^2 - (2/\sqrt{3} )^2}{2^2 + (2/\sqrt{3})^2 }$

         = (4 - 4/3)/(4+4/3)

         = (8/3)/(16/3)

         = 8/16 = 1/2

I hope it helps please mark me as brainliest...