Question

help me please...

..
..
.​

Answer 1

$\implies \tan \theta \: = \frac{p}{q} \\ \\ \implies \: \frac{p \sin \theta - q \cos \theta}{p \sin \theta + q \cos \theta} \\ \\ \implies \: \frac{ \cancel{ \cos \theta}(p \tan \theta - q)}{ \cancel{ \cos \theta}( p \tan \theta + q)} \\ \\ \implies \: \frac{ \frac{p.p}{q} - q }{ \frac{p.p}{q} + q} \\ \\ \implies \: \frac{ \frac{ {p}^{2} - {q}^{2} }{ \cancel{q}} }{ \frac{ {p}^{2} + {q}^{2} }{ \cancel{q}} } \\ \\ \implies \: \frac{ {p}^{2} - {q}^{2} }{ {p}^{2} + {q}^{2} }$

__________________________

thanks

Answer 2

Answer:

your answer is in attachment

hope it helps