Question

help me ... please...​

Answer 1

Answer:

POR=75°

SOQ=75°(V.O.A)

ROQ=105°

POS=105°(V.O.A

Step-by-step explanation:

POR:ROQ=5:7

LET THE ANGLES BE 5x,7x

5x+7x=180°(linear pair)

12x=180°

x=180/12

x=15°

So, POR=5×15=75°

ROQ=7×15=105°,

Hence, POR=75°

SOQ=75°(V.O.A)

ROQ=105°

POS=105°(V.O.A)

Answer 2

Step-by-step explanation:

when two lines are intersected the opposite angles are always equal

let us assume <por = w ,<roq = x,<qos = y ,

<sop = z

we know that opposite angles are equal so

<por = <soq ==>w = y

<roq = <sop ==>x =z

given that <por : <roq = 5:7

we know that w+x+y+z = 360°

2w + 2x = 360°

w + x = 180°

5j + 7j =180°

j = 15°

5j = 5 ×15 =75 °

7j = 7×15 = 105°

<por = <soq ==>w = y = 75°

<roq = <sop ==>x =z = 105°